Atlas home || Conferences | Abstracts | about Atlas

International Congress on Differential Geometry in memory of Alfred Gray (1939-1998)
September 18-23, 2000
Universidad del País Vasco
Bilbao, Spain

Organizers
M. Fernández (chairman), R. Ibáñez, M. Macho-Stadler

View Abstracts
Conference Homepage

Gauss curvatures and tube for polyhedron
by
Jin-ichi Itoh
Kumamoto University, Japan

Oral Communication

We define some curvatures of polyhedron which corresponds to Gauss curvature and show Gauss's Theorema Egregium, Chern-Lashof's inequality and Weyl's volume formula of tube for polyhedron.

When a d dimensional combinatorial manifold P in Rd+1 satisfies the following (i) and (ii), we call it a d dimensional polyhedral manifold. (i) For any m dimensional simplex \sigmam has a flat metric such that \sigmam coincides with a linear simplex in Rm+1. (ii) For any vertex v, locally embedded around each vertex. We say a vertex v with it property (*), if there is a point n in Sd such that for any normal vecor ni of face around v \angle(ni, n) < \frac\pi2,

We define the intrinsic curvature Ki(v) at a vertex v in P by
Ki(v): = n
å
m=0 
(-1)m
å
\sigmajm \owns v 
\betajm,
where \betam is the outer angle of m-simplex at v. Next we will define the extrinsic curvature only 2-dimensional case. We denote the faces of P around v by {fi}  (i=1, ... , k), its unit normal vectors of one side by {ni}, where the order of indices i is anti-clockwise looking from the side of normal directions. Let cj, j+1 be a great arc from nj to nj+1 on S2. We define the closed brocken great arcs c by c: = c1, 2 \cup c2, 3 \cup ... \cup ck, 1 and define Ke(v, n) by the signed area of enclosed domain by c with respect to a base point n as follows. We denote the oriented spherical triangle with vertices n,   nj,   nj+1 by T(j). Let J+ (resp. J-) be the subset of {1, ... , k} such that the orientation of T(j) is anti-clockwise (resp. clockwise). We define Ke(v, n) by
Ke(v, n) : = \frac12\pi(
å
j in J+ 
Area(T(j)) -
å
j in J- 
Area(T(j)))
When a polyhedron P has property (*), the value of Ke(v, n) does not depend on the choice of n, then we write it Ke(v) and call it the extrinsic curvature of v. We omit the definition of general dimension. Note that the above definition is different from Banchoff's one.

Theorem(Theorema egregium for polyhedron) For any d-dimensional polyhedron P in Rd+1 and vertex v in P with property (*) it holds that Ki(v) = Ke(v).

It is well known that Gauss-Bonnet type equality holds (i.e. \sumv in P Ki(v) = \chi(P) , where \chi(P) denote the Euler number of P.) We consider the total absolute curvature for a 2-dimensional polyhedron. We denote the domains devived by the boundaries of spherical triangle T(j) by D(i). For each domain D(i) define the number mi by mi +/- : = # {j in J +/- | D(i) subset T(j) },  mi : = mi+ - mi-. Define the absolute curvature Ka(v) at v by
Ka(v) : = \frac12\pi
å
i 
|mi| Area(D(i)).

Theorem (Chern-Lashoff type ineq. for polyhedron) For any d-dimensional polyhedron P in Rd+1 satisfying property (*) at all vertices it holds that

å
v in P 
Ka(v) >= b(P),
where b denotes the sum of all dimensional Betti numbers.

The Weyl's volume formula of tube for a closed surface M in R3 says that for enough small positive number r, Vol Vr(M) = 2r Area M + \frac2r33 \intM K dv, where Vr(M) denotes the r neighborhood of M, K denotes Gauss curvature on M. Let P be a 2-dimensional polyhedron in R3 . We assume for simplicity that the number of face around v is three. We define some kind of curvature [K\tilde](v) at v as follows. Let Tj   (j=1, 2, 3) be the tangent plane of S2 at nj, and Tj+ (resp. Tj-) be the half space with boundary Tj and containing (resp. not containing) the origin. Let Hj be the plane through the origin and two vertices except nj , and Hj+ (resp. Hj- ) be the half space with boundary Hj and not containing (resp. containing) nj. Put q: = \cap j=1n Tj. When q in \cap j=1, 2, 3Hj+, define [K\tilde](v) by the volume of \cap j=1, 2, 3Hj+ \cap \cap j=1, 2, 3Tj+. When q in Hj- \cap Hj+1+ \cap Hj+2+, define [K\tilde](v) by
Vol(
Ç
j=1, 2, 3 
Hj+ \cap
Ç
j=1, 2, 3 
Tj+)- Vol(Hj- \cap Hj+1+ \cap Hj+2+ \cap Tj- \cap Tj+1+ \cap Tj+2+).

Theorem (Weyl type volume formula of tube for polyhedron) For any polyhedron P in R3 and enough small positive number r, it holds that
Vol Vr(P) = 2r Area(P) + \frac2r33
å
v in P 
~
K
 
(v).

Under an adequate definition of Ki for d dimensional closed polyhedron P in Rd+1 it holds that if d is odd (resp. even),
Vol Vr(P) = 2{ r Area(P) + \fracr33 Kd-3(P) + ... +\fracrdd K0(P)   (resp.   \fracrd-1d-1 K1(P) ) }.

Date received: May 27, 2000


Copyright © 2000 by the author(s). The author(s) of this document and the organizers of the conference have granted their consent to include this abstract in Atlas Conferences Inc. Document # cadq-68.