|
Organizers |
On Piecewise Smooth Maps of a Circle
by
Akhtam A. Dzhalilov
Mechanics and Mathematics Faculty of Samarkand State University, Boulevard St.15, Samarkand 703004, Uzbekistan
In the present work we study piecewise smooth circle homeomorphisms i.e., maps that
are smooth everywhere except several singularities where the first derivative
is discontinuous. We consider the orientation-
preserving homeomorphism Tfx of the unit circle,
|
|
Condition (d) means that the function f(x) belongs to the class C2 on any connected component of the set S1 \{ xpi, i = [`0, m]}.
Let the rotation number \rho = \rho(f) is irrational. Denjoy showed that if f(x) in C1 (R1) and varS1 logf'(x) < \infty, then there exists a circle homeomorphism; Tj such that Tj o Tf=T\rho o Tj where T\rhox={ x+\rho}, is the linear rotation of the circle through an angle of \rho. An important problem in circle maps theory is to find relations between the smoothness of f , the properties of the rotation number \rho , and the smoothness class of the conjugation Tj. This problem is closely related to the existense problem for an absolutely continuous (a.c.) invariant measure for Tf . Indeed, a unique probability invariant measure for Tf is a.c. w.r.t., the Lebesgue measure iff j(x) is an absolutely continuous function. This consideration was first used by Arnold [A] to study smoothness of j(x). The strongest results in this field were obtained by Herman, Yoccoz, Katznelson and Ornstein, Sinai and Khanin.
In turns out that the situation becomes diametrically opposite in the presence of a single point xc of break-type singularity. Namely, if f(x) in C2+ \epsilon ( S1 \xc ) for some \epsilon > 0, then an invariant measure is always singular w.r.t. Lebesgue measure [D]. Now we formulate our main results.
Theorem 1. Assume that a function f(x) defining a homeomorphism Tf satisfies conditions (a)-(d), \prodi=0m ci =/= 1 and the rotarion number \rho = \rho(f) is irrational. Then the invariant measure \mu is singular w.r.t. the Lebesgue measure \lambda , i.e. there exists a measurable subset A subset S1 such that \mu(A)=1 and \lambda(A)=0.
Definition 1. Two measures \nu1 and \nu2 on the same \sigma- algebra are L2-equivalent if \nu1=j1 (\nu2) with j1 in L2 (\nu1) and \nu2=j2 (\nu1) with j2 in L2 (\nu2).
Definition 2. Let \rho be irrational number and its continuous fraction expansion be \rho = [k1, k2, ..., kn, ...]. If kn <= const, n >= 1, then we say that \rho is of bounded type.
Theorem 2. Suppose that a function f(x) defining a homeomorphism Tf satisfies condititons (a)-(d), \prodi=0mci=1 and the rotation number \rho = \rho(f) is irrational of bounded type. Then the invariant measure \mu and the Lebesgue measure \lambda are L2-equivalent.
[A]. Arnold V.I. "Small denominators, I. Mapping the circle onto itself", Izv.Akad.Nauk SSSR, Ser.Matem., 25, 1, p. 21-86, (1961).
[D] Dzhalilov A.A. and Khanin K.M., Ön an invariant measure for homeomorphisms of a circle with a point of break", Functional Analysis and its Appl., v.32, 3, p.153-161, (1998).
Date received: February 24, 2004
Copyright © 2004 by the author(s). The author(s) of this document and the organizers of the conference have granted their consent to include this abstract in Atlas Conferences Inc. Document # calu-91.