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18th International Conference on Operator Theory
June 27 - July 1, 2000
University of the West
Timisoara, Romania

Organizers
Dumitru Gaspar, Traian Ceausu, Aurelian Craciunescu, Aurelian Gheondea, Radu-Nicolae Gologan, Ciprian Pop, Dan Popovici, Nicolae Suciu, Alexandru Terescenco, Dan Timotin, Flavius Turcu

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On existence of analytic solutions of (k+1)-times integrable Cauchy problem
by
Volodymyr M. Gorbachuk
National Technical University of Ukraine (Kyiv Polytechnic Institute)

Let A be a closed linear operator on a Banach space B. We say that a vector x in \cap n in N0D(An),  N0 = {0, 1, 2, ...}, is of finite order if for sufficiently large n in N0 there exists \gamma in R1 such that
||Anx|| <= nn\gamma.
The greatest lower bound \beta = \beta(x) of such \gamma is called the order of x. By the type of a vector x of order \beta we mean the number
\alpha = \alpha(x) = inf
{\delta > 0: ||Anx|| <= \deltannn\beta,  n in N0  is sufficiently large}.

Let 0 < \tau <= \infty. Consider the following Cauchy problem:
Ck+1(\tau)     ì
ï
ï
í
ï
ï
î
y
in
C([0, \tau), D(A)) \cap C1([0, \tau), B),
y'(t)
=
Ay(t) + \fractkk!x,     t in [0, \tau),
y(0)
=
0
(k in N0 is fixed). The problem of finding a solution y(t) of Ck+1(\tau) is called k+1-times integrated Cauchy problem [1]. The problem Ck+1(\tau) is well posed if for any x in B there exists a unique solution of this problem.

We discuss the conditions on a vector x under which the problem Ck+1(\tau) has a solution analytic in a neighborhood of zero, and if this is the case, when such a solution can be extended to an entire vector-function of finite order and type. We show that the following assertion holds.

Theorem. The Cauchy problem Ck+1(\tau) has a solution analytic in a neighborhood of zero if and only if \beta(x) <= 1. In order that the solution admit an extension to an entire vector-function, it is necessary and sufficient that one of the below conditions be satisfied:

(i)  \beta(x) < 1;

(ii)  \beta(x) = 1,  \alpha(x) = 0.

The following relationship between the order \rho and type \sigma of an entire solution y(t) of Ck+1(\tau) and the order \beta and type \alpha of the vector x holds:
\rho = \frac11 - \beta,     \sigma = \frac(\alphae)\rho\rhoe.

It is not hard to give an example of the operator A such that for any \tau the problem Ck+1(\tau) is well posed, but there is no nontrivial solution analytic in a neighborhood of zero. We prove that in the case where A is a normal operator on a Hilbert space, the problem Ck+1(\tau) has solutions in the class of entire vector-functions of order \rho <= 1, and the set of such solutions is dense in the set of all solutions. If A is the generator of an analytic semigroup of bounded linear operators on B, then the set of all entire solutions of the problem Ck+1(\tau) is also dense in the set of all its solutions.

#1 W. Arendt, O. El-Mennaoui, and V. Keyantuo, Local integrated semigroups: evolution with jumps og regularity, J. Math. Anal. Appl. 186 (1994), 572-595.

Date received: May 31, 2000


Copyright © 2000 by the author(s). The author(s) of this document and the organizers of the conference have granted their consent to include this abstract in Atlas Conferences Inc. Document # caeo-42.