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Organizers |
Lattice effect algebras possessing two-valued states
by
Jan Paseka
Department of Mathematics and Statistics, Faculty of Science, Masaryk University, Janackovo nam. 2a, 602 00 Brno, Czech Republic
Coauthors: Zdena Riecanova, Department of Mathematics, Faculty of Electrical Engineering and Information Technology, Slovak University of Technology
Ilkovicova 3, SK-812 19Bratislava, Slovak Republic, zdena.riecanova@gmail.com
Common generalizations of MV-algebras [] and orthomodular lattices are lattice effect algebras []. An effect algebra (E;⊕, 0, 1) is a set E with two special elements 0, 1 and a partial binary operation ⊕ which is commutative and associatiove at which these equalities hold if one of their sides exists. Moreover, to every element a ∈ E there exists a unique element a' ∈ E with a⊕a'=1 and if a⊕1 exists then a=0. In every effect algebra we can define a partial order by a ≤ b iff there exists c ∈ E with a⊕c=b (we set c=b\ominus a). If (E; ≤ ) is a lattice (a complete lattice) then (E;⊕, 0, 1) is called a lattice effect algebra (a complete lattice effect algebra).
Generalized effect algebras as posets are unbounded versions of effect algebras. In this case instead of the axiom on the existence of a' with a⊕a'=1 for all a ∈ E we have cancellation law, i.e., a⊕b=a⊕c implies b=c and, moreover, a⊕b=0 implies a=b=0.
A well known fact is that every generalized effect algebra P can be uniquely extended onto effect algebra E (called an effect algebraic extension of P) in which P is an order ideal in E and P*=E\P is a dual poset to P. We write E=P[(∪)\dot] P* (a disjoint union) []. On the other hand not every (lattice) effect algebra E becomes this way. We can prove
[] Let (E;⊕, 0, 1) be an effect algebra. The following conditions are equivalent:
For Archimedean atomic lattice effect algebra E we can show a sufficient condition (F) for the existence of a two-valued state w on E:
(F) There exists a finite set F={pk | k ∈ H} of pairwise noncompatible atoms of E such that for every atomic block M of E there exists kM ∈ H such that pkM ∈ C(M) and w(pkM)=1. []
Moreover, we can prove that this condition (F) is a necessary and sufficient condition for the existence of a two-valued state w on: (a) every (o)-continuous Archimedean atomic lattice effect algebra, (b) every block-finite Archimedean atomic lattice effect algebra. Here a block of a lattice effect algebra is a maximal sub-lattice effect algebra being an MV-algebra. A lattice effect algebra is called block-finite if it has only finitely many blocks.
Using this facts we can prove
[] Every Archimedean atomic lattice effect algebra with at most five blocks possess a state.
Note that in present time the known example of finite lattice effect algebra admitting no states has nineteen blocks.
Finally, since the existence of a two-valued state w on an effect algebra E is equivalent to the fact that E is an effect algebraic extension of a sub-generalized effect algebra Pw={x ∈ E | w(x)=0}, the following question arises:
If F1 and F2 are two sets of pairwise noncompatible atoms of an Archimedean atomic lattice effect algebra E and w1, w2 are two-valued states on E at which PF1=w-11({0}) and PF2=w-12({0}) are sub-generalized effect algebras of E with E=PF1[(∪)\dot] P*F1=PF2[(∪)\dot] P*F2 whether (or at which conditions) PF1 and PF2 are isomorphic generalized effect algebras.
We show that two non-isomorphic generalized effect algebras PF1 and PF2 may have a common (or isomorphic) effect algebraic extension.
In spite of the fact that an atomic lattice effect algebra E may have nonatomic block [] the following statement can be proved:
[] Let E be an Archimedean atomic lattice effect algebra and F1, F2 are two sets of pairwise noncompatible atoms satisfying the condition (F). Let there exists a bijection y:F1→ F2 such that, for every atomic block M of E we have a ∈ M∩F1 ⇔ y(a) ∈ M∩F2. Then PF1 ≅ PF2.
This very simple condition is not necessary for the isomorphism of PF1 and PF2. The necessary and sufficient condition for PF1 and PF2 is the following:
[] Let E1, E2 be Archimedean atomic lattice effect algebras, F1 ⊆ E1, F2 ⊆ E2 are two sets of pairwise noncompatible atoms satisfying the condition (F). Let M1, M2 are families of all atomic blocks of E1 and E2 respectively. Then the condition (i) implies the conditions (ii) and (iii):
| (i) |
| (a) |
Date received: February 22, 2008
Copyright © 2008 by the author(s). The author(s) of this document and the organizers of the conference have granted their consent to include this abstract in Atlas Conferences Inc. Document # cavs-15.