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Analysis and Topology, Lviv - 2008
May 26 - June 7, 2008
Ivan Franko National University of Lviv
Lviv, Ukraine

Organizers
M.Zarichnyi, O.Skaskiv, T.Banakh (Lviv University)

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Constructing small subsets with a given packing index in Abelian groups
by
Nadia Lyaskovska
Ivan Franko Lviv National University

For a subset A of a group G, we consider the following two cardinal numbers
indP(A)= sup
{|S|:S ⊂ G is such that {xA}x ∈ S is disjoint}
and
IndP(A)= sup
{|S|:S ⊂ G is such that{xA}x ∈ S is almost disjoint},
called the packing indexes of A in G.

Those packing indexes have sharp versions carrying a bit more information about A:
ind+P(A)= sup
{|S|+:S ⊂ G is such that {xA}x ∈ S is disjoint}
and
Ind+P(A)= sup
{|S|+:S ⊂ G is such that{xA}x ∈ S is almost disjoint}.
It follows that indP(A)=sup{k:k < ind+P(A)} and indP(A) ≤ IndP(A). The (sharp) packing indexes measure the geometric smallness of a subset of a group. Subsets with small packing index can be thought as large in a geometric sense.

Theorem 1 Let G be an infinite Abelian group and L ⊂ G be a subset with IndP(L)=1. For a cadinal k ∈ [2, |G|+] the following conditions are equivalent:


    1) there is a subset A ⊂ G with indP+(A)=k;
    2) there is a subset A ⊂ L with ind+P(A)=Ind+P(A)=k;
    3) if |G/[G]2| ≤ 2, then k ≠ 4 and if G=[G]3, then k ≠ 3.

Here [G]p={x ∈ G:xp=1} stands for the subgroup of elements of order p.

Observe that the equality IndP(L)=1 is equivalent to |L∩(g+L)|=|G| for all g ∈ G, which means that L is rather large in a geometric sense. Still such a set L can be presented as union of small sets.

Theorem 2 Each infinite group G contains two subsets A, B ⊂ G such that indP+(A)=indP+(B)=|G|+ but IndP(A∪B)=1.

Date received: May 7, 2008


Copyright © 2008 by the author(s). The author(s) of this document and the organizers of the conference have granted their consent to include this abstract in Atlas Conferences Inc. Document # cawm-54.